b:head_first_statistics:using_the_normal_distribution

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b:head_first_statistics:using_the_normal_distribution [2025/10/26 23:36] – [Pool Puzzle] hkimscilb:head_first_statistics:using_the_normal_distribution [2025/10/29 02:12] (current) – [All aboard the Love Train] hkimscil
Line 146: Line 146:
 [1] 0.9406201 [1] 0.9406201
 > pnorm(-1.56, lower.tail = FALSE) > pnorm(-1.56, lower.tail = FALSE)
 +[1] 0.9406201
 +> pnorm(-1.56, 0, 1, lower.tail = F)
 [1] 0.9406201 [1] 0.9406201
 > pnorm(64, 71, sqrt(20.25), lower.tail = FALSE) > pnorm(64, 71, sqrt(20.25), lower.tail = FALSE)
Line 828: Line 830:
  
 <WRAP box> <WRAP box>
-를 R을 이용하여 구하+를 R에서 해보면 
 <code> <code>
-pbinom(5, 12, 1/2)+> dbinom(0, 12, 1/2) + dbinom(1, 12, 1/2) + dbinom(2, 12, 1/2)  
 +>  + dbinom(3, 12, 1/2) + dbinom(4, 12, 1/2) + dbinom(5, 12, 1/2) 
 +[1] 0.387207
 </code> </code>
 +그러나, R에서는 더 간단한 방법으로 
 <code> <code>
 > pbinom(5, 12, 1/2) > pbinom(5, 12, 1/2)
Line 838: Line 842:
 </code> </code>
  
-는 아래와 같음을 이해해야 한+그리고, 의 dbinom으로 하나씩 계산한다고 하더라도 아래처럼 하게 된
 <code> <code>
 > sum(dbinom(c(0:5),12,1/2)) > sum(dbinom(c(0:5),12,1/2))
Line 971: Line 975:
 {{:b:head_first_statistics:pasted:20191118-113020.png}} {{:b:head_first_statistics:pasted:20191118-113020.png}}
  
-$\lambda > 15$ 일 때, Poisson distribution, $X \sim Po(\lambda)$는 $X \sim N(\lambda, \lambda)$ 의 성격을 취한다.+<fc #ff0000>$\lambda > 15$ 일 때,</fc> Poisson distribution, $X \sim Po(\lambda)$는 $X \sim N(\lambda, \lambda)$ 의 성격을 취한다.
  
 예)  예) 
Line 1020: Line 1024:
  
 $0.9654916 \sim 0.9656205$ $0.9654916 \sim 0.9656205$
 +
 +R에서 ppois을 이용하면
 +<code>
 +> ppois(51, 40)
 +[1] 0.9612598
 +
 +
 +</code>
  
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b/head_first_statistics/using_the_normal_distribution.1761521779.txt.gz · Last modified: by hkimscil

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