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anova [2020/05/20 15:13] – [Example] hkimscilanova [2020/05/20 15:51] – [Example 2] hkimscil
Line 518: Line 518:
  
 ====== Example ====== ====== Example ======
 +가설. 단어맞히기 게임에서 첫글자를 힌트로 주거나, 마지막 글자를 힌트로 주거나, 힌트를 주지 않은 세 그룹 간에 틀린 단어의 숫자에 차이가 있을 것이다. 
 +
 |  |First Letter \\ Condition 1 \\ X<sub>1</sub>|Last Letter \\ Condition 2 \\ X<sub>2</sub>|No Letter \\ Condition 3 \\ X<sub>3</sub> | |  |First Letter \\ Condition 1 \\ X<sub>1</sub>|Last Letter \\ Condition 2 \\ X<sub>2</sub>|No Letter \\ Condition 3 \\ X<sub>3</sub> |
 | | 15 | 21 | 28 | | | 15 | 21 | 28 |
Line 536: Line 538:
 | a = $\sum{(X_i)^2}$  | 3888  | 5868  | 7614  | | a = $\sum{(X_i)^2}$  | 3888  | 5868  | 7614  |
 | a-b = Var.within  | 648  | 108  | 324  | $f = $1080   | | a-b = Var.within  | 648  | 108  | 324  | $f = $1080   |
 +
 \begin{eqnarray*} \begin{eqnarray*}
 a & = & \sum (X_i)^2 = 17370 \\ a & = & \sum (X_i)^2 = 17370 \\
Line 545: Line 548:
 g & = & SS_{between} = e - f = 420   g & = & SS_{between} = e - f = 420  
 \end{eqnarray*} \end{eqnarray*}
 +
 +| m.total = Mean.total  | $b = \; $ 23  |||
 +| m.within = Mean.each.group  | 18  | 24  | 27  |
 +| o = m.total - m.within  | 5   | -1  | -4  |
 +| o%%^%%2  | 25  | 1  | 16  |
 +| n  | 10  | 10  | 10  |
 +| o%%^%%2 * n | 250  | 10  | 160  |
 +| sum  | $g = \; $ 420  |||
 +
  
 \begin{eqnarray*} \begin{eqnarray*}
-k =  3 \\ +3 \\ 
-n =  10 \\ +10 \\ 
-N =  30 \\+30 \\
 \end{eqnarray*} \end{eqnarray*}
  
 \begin{eqnarray*} \begin{eqnarray*}
-df_{between} =  \\ +e' & = & df_{between} =  \\ 
-df_{within} =  \\ +f' & = & df_{within} =   \\ 
-df_{total} =  \\ +g' & = & df_{total} =  \\ 
 \end{eqnarray*} \end{eqnarray*}
  
-<code>x1 <- c(15, 20, 14, 13, 18, 16, 13, 12, 18, 41)+|          | SS   | df    | MS  | F   | 
 +| between  | $e = \;$ 420   | $e' = \;$ 2 | 210  |  210/40 = 5.25  | 
 +| within   | $f = \;$ 1080  | $f' = \;$ 27 | 40  |   | 
 +| total    | $g = \;$ 1500  | $g' = \;$ 29 |     | 
 + 
 +F<sub>crit</sub>(2, 27) =  3.35 
 +F<sub>cal</sub> = 5.25 
 + 
 +F<sub>cal</sub> > F<sub>crit</sub> 이므로 3집단 간의 평균은 통계학적으로 의미가 있는 차이를 가지고 있다. 
 +====== Example 2 ====== 
 +<code> 
 +x1 <- c(15, 20, 14, 13, 18, 16, 13, 12, 18, 41)
 x2 <- c(21, 25, 29, 18, 26, 22, 26, 24, 28, 21) x2 <- c(21, 25, 29, 18, 26, 22, 26, 24, 28, 21)
 x3 <- c(28, 30, 32, 28, 26, 30, 25, 36, 20, 15) x3 <- c(28, 30, 32, 28, 26, 30, 25, 36, 20, 15)
 </code> </code>
  
-<code>> data.frame(x1,x2,x3)+<code>> xc <- data.frame(x1,x2,x3)
    x1 x2 x3    x1 x2 x3
 1  15 21 28 1  15 21 28
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 <code> <code>
-> colnames(xs[1]) <- "wrong" +> colnames(xs)  <- c("wrong""condition")
-> colnames(xs[2]) <- "cond"+
 </code> </code>
  
-<code># cf+<code> 
 +# cf
 # lengthofelements <- length(x1) # lengthofelements <- length(x1)
 # varofvariable <- var(x1)</code> # varofvariable <- var(x1)</code>
  
 <code> <code>
-df_x1 +df.total <- length(xs$wrong) - 1 
-df_x2 +ss.total <- var(xs$wrong)*df_tot 
-df_x3+var.total <- ss.total/df.total 
 +var.total.r <- var(xs$wrong)
  
-ss_x1 +df.x1 <- length(x1)-1 
-ss_x2 +df.x2 <- length(x2)-1 
-ss_x3+df.x3 <- length(x3)-1 
 +ss.x1 <- var(x1)*df.x1 
 +ss.x2 <- var(x2)*df.x2 
 +ss.x3 <- var(x3)*df.x3
  
-df_bet +ss.within <- ss.x1 + ss.x2 + ss.x3 
-ss_bet+df.within <- df.x1 + df.x2 + df.x3 
 +ss.between <- ss.total - ss.within 
 +df.between <- df.total - df.within
  
-df_tot +ms.between <- ss.between/df.between 
-ss_tot+ms.within <- ss.within/df.within 
 +f.value <- ms.between/ms.within
  
-df_with +ss.between 
-ss_with+df.between
  
-df_bet +ss.within 
-ss_bet+df.within
  
-</code>+ms.between 
 +ms.within 
 + 
 +f.value 
 + 
  
-<code> 
-df_tot <- length(xs$ind) - 1 
-ss_tot <- var(xs$values)*df_tot 
-var_tot <- var(xs$values) 
  
-df_x1 <- length(x1)-1 
-df_x2 <- length(x2)-1 
-df_x3 <- length(x3)-1 
-ss_x1 <- var(x1)*df_x1 
-ss_x2 <- var(x2)*df_x2 
-ss_x3 <- var(x3)*df_x3 
 </code> </code>
 ====== E.G. 1 (R) ====== ====== E.G. 1 (R) ======
anova.txt · Last modified: 2022/09/30 09:02 by hkimscil

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