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mean_and_variance_of_poisson_distribution [2020/11/21 01:50] – [Mean] hkimscilmean_and_variance_of_poisson_distribution [2020/11/21 02:22] (current) hkimscil
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 +====== Mean and Variance of Poisson Distribution ======
 ====== Mean ====== ====== Mean ======
 Mean Poisson distribution = $\lambda$ Mean Poisson distribution = $\lambda$
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 & = & \lambda \cdot e^{-\lambda} \cdot \sum_{y=0}^{\infty} \frac{\lambda^{y}}{(y)!} \\ & = & \lambda \cdot e^{-\lambda} \cdot \sum_{y=0}^{\infty} \frac{\lambda^{y}}{(y)!} \\
 & = & \lambda \cdot e^{-\lambda} \cdot \underline{\sum_{y=0}^{\infty} \frac{\lambda^{y}}{(y)!}} \\ & = & \lambda \cdot e^{-\lambda} \cdot \underline{\sum_{y=0}^{\infty} \frac{\lambda^{y}}{(y)!}} \\
-\text{from Taylor series\\+\text{recall: } \; \\  
 +e^{a} = \sum_{y=0}^{\infty} \frac{a^y}{y!} \\
 & = & \lambda \cdot e^{-\lambda} \cdot e^{\lambda} \\ & = & \lambda \cdot e^{-\lambda} \cdot e^{\lambda} \\
 & = & \lambda \\ & = & \lambda \\
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-====== Variance ======+ ====== Variance ====== 
 +Variance는 위의 binomial 케이스처럼 좀 복잡하다. 
 Variance of Poisson distribution = $\lambda$ Variance of Poisson distribution = $\lambda$
 +
 +\begin{eqnarray*}
 +Var(X) & = & E \left[(X-\mu)^2 \right] \\
 +& = & \sum_{x=1}^{n}(x-\mu)^2 \cdot p(x) \\
 +\end{eqnarray*}
 +
 +또한 
 +\begin{eqnarray*}
 +E \left[(X-\mu)^2 \right] 
 +& = & E(X^2) - \left[E(X) \right]^2 \\
 +\end{eqnarray*}
 +
 +이 중에서 우선 $E(X^2)$을 우선 다루면
 +\begin{eqnarray*}
 +E(X^2) & = & \sum_{x=1}^{n}x^2 \cdot p(x) \\
 +& = & \sum_{x=1}^{n}x^2 \cdot \frac{e^{-\lambda} \cdot \lambda^{x}}{x!}\\
 +& = & e^{-\lambda} \cdot \sum_{x=1}^{n}x^2 \cdot \frac{\lambda^{x}}{x!}\\
 +\end{eqnarray*}
 +
 +이상태로는 $X^2$를 없앨 수는 없으므로 계산을 우회하기로 하면
 +
 +\begin{eqnarray*}
 +E[X(X-1)] & = & \sum_{x=0}^{\infty} x(x-1) \cdot p(x) \\
 +& = & \sum_{x=0}^{\infty} x(x-1) \cdot \frac{e^{-\lambda} \cdot \lambda^{x}} {x!} \\
 +& = & e^{-\lambda} \cdot \sum_{x=2}^{n} x(x-1) \cdot \frac{\lambda^{x}}{x(x-1) \cdot (x-2)!} \\
 +& = & e^{-\lambda} \cdot \sum_{x=2}^{n} \frac{\lambda^{x}}{(x-2)!} \\
 +& = & e^{-\lambda} \cdot \sum_{x=2}^{n} \frac{\lambda^2 \cdot \lambda^{x-2}}{(x-2)!} \\
 +& = & \lambda^2 \cdot e^{-\lambda} \cdot \sum_{x=2}^{n} \frac{\lambda^{x-2}}{(x-2)!} \\
 +\text{let } \; y = x-2 \\
 +& = & \lambda^2 \cdot e^{-\lambda} \cdot \underline{\sum_{y=0}^{n} \frac{\lambda^{y}}{y!}} \\
 +& = & \lambda^2 \cdot e^{-\lambda} \cdot \underline{\sum_{y=0}^{n} \frac{\lambda^{y}}{y!}} \\
 +\text{underlined part } = e^{\lambda} \\
 +& = & \lambda^2 \cdot e^{-\lambda} \cdot e^{\lambda} \\
 +& = & \lambda^2 
 +\end{eqnarray*}
 +
 +따라서 
 +\begin{eqnarray*}
 +E[X(X-1)] & = & E[X^2-X] = E(X^2) - E(X) \\
 +& = & \lambda^2  \\
 +E(X^2) & = & \lambda^2 + \lambda \\
 +\end{eqnarray*}
 +
 +다시 원래대로 돌아가서
 +\begin{eqnarray*}
 +Var(X) & = & E \left[(X-\mu)^2 \right]  \\
 +& = & E(X^2) - \left[E(X) \right]^2 \\
 +& = & \lambda^2 + \lambda - \lambda^2 \\
 +& = & \lambda 
 +\end{eqnarray*}
 +
 +
 +
  
mean_and_variance_of_poisson_distribution.1605891028.txt.gz · Last modified: 2020/11/21 01:50 by hkimscil

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