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r:probability [2019/10/04 10:14] – [pnorm, qnorm] hkimscilr:probability [2019/10/04 10:27] (current) – [qt, pt] hkimscil
Line 39: Line 39:
 Assume that the test scores of a college entrance exam fits a normal distribution. Furthermore, the mean test score is 72, and the standard deviation is 15.2. What is the percentage of students scoring 84 or more in the exam? Assume that the test scores of a college entrance exam fits a normal distribution. Furthermore, the mean test score is 72, and the standard deviation is 15.2. What is the percentage of students scoring 84 or more in the exam?
  
-> pnorm(72, mean=72, sd=15.2, lower.tail=FALSE)+<code>> pnorm(72, mean=72, sd=15.2, lower.tail=FALSE)
 [1] 0.5 [1] 0.5
 +
 +> pnorm(1.96)
 +[1] 0.9750021
 +
 +> pnorm(1.96)-pnorm(-1.96)
 +[1] 0.9500042
 +
 +> pnorm(c(1.96, -1.96))
 +[1] 0.9750021 0.0249979
  
 > pnorm(84, mean=72, sd=15.2, lower.tail=FALSE) > pnorm(84, mean=72, sd=15.2, lower.tail=FALSE)
Line 47: Line 56:
 > qnorm(.2149176, mean=72, sd=15.2, lower.tail=FALSE) > qnorm(.2149176, mean=72, sd=15.2, lower.tail=FALSE)
 [1] 84 [1] 84
-</WRAP>+</code></WRAP> 
 +===== rnorm ===== 
 +Random samples from a normal distribution 
 +<code>> set.seed(1024) 
 +> rnorm(50) 
 + [1] -0.778662882 -0.389476396 -2.033798329 -0.982373104  0.247890054 
 + [6] -2.103864629 -0.381418049  2.074919838  1.027138407  0.473014228 
 +[11] -1.879263193 -1.239189026  1.160418602  0.003671291 -0.095452066 
 +[16]  1.795551228 -1.322138481 -0.276086413 -0.743976510 -1.070050125 
 +[21] -0.349525474  0.805559661  1.605301660  1.447595754 -0.128302224 
 +[26] -0.538926447  0.391586050  0.879217023 -0.824732092  0.732876423 
 +[31] -0.664914510  0.360885549  1.011930957 -0.235916848  1.353589893 
 +[36] -0.268632965  1.019877368 -0.279706500 -0.618146278 -0.499273059 
 +[41] -0.153716777  1.220869694 -0.669570510 -1.209660342  1.024096655 
 +[46]  0.603955311 -0.568653469 -0.891303117 -2.525145692  0.589357049</code> 
  
 ===== qt, pt ===== ===== qt, pt =====
Line 70: Line 94:
 > qt(c(0.025, 0.975), df=50) > qt(c(0.025, 0.975), df=50)
 [1] -2.008559  2.008559 [1] -2.008559  2.008559
 +
 +. . . . . .
 +
 +> qt(c(0.025, 0.975), df=50000)
 +[1] -1.960011  1.960011
 +
 </code> </code>
 </WRAP> </WRAP>
r/probability.1570151691.txt.gz · Last modified: 2019/10/04 10:14 by hkimscil

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