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sequential_regression [2019/10/18 07:24] – [r] hkimscilsequential_regression [2019/10/18 07:33] – [r] hkimscil
Line 197: Line 197:
 $method $method
 [1] "pearson" [1] "pearson"
 +
 +## zero-order correlation
 +> cor(datavar)
 +            bankaccount     income     famnum
 +bankaccount   1.0000000  0.7944312 -0.6922935
 +income        0.7944312  1.0000000 -0.3999614
 +famnum       -0.6922935 -0.3999614  1.0000000
 +
  
 </code> </code>
Line 214: Line 222:
  
  
 +|  | bankaccount  | income  | famnum   
 +| bankaccount  | 1.0000000  | 0.7944312  | -0.6922935 
 +| income  | 0.7944312  | 1.0000000  | -0.3999614   
 +| famnum  | -0.6922935  | -0.3999614   | 1.0000000    | 
 +
 +<code>
 +pcor.test(datavar$bankaccount, datavar$income, datavar$famnum)
 +pcor.test(datavar$bankaccount, datavar$famnum, datavar$income)
 +
 +spcor.test(datavar$bankaccount, datavar$income, datavar$famnum)
 +spcor.test(datavar$bankaccount, datavar$famnum, datavar$income)
 +</code>
 +. . . 
 +<code>
 +> pcor.test(datavar$bankaccount, datavar$income, datavar$famnum)
 +   estimate    p.value statistic  n gp  Method
 +1 0.7825112 0.01267595  3.325102 10  1 pearson
 +> pcor.test(datavar$bankaccount, datavar$famnum, datavar$income)
 +   estimate    p.value statistic  n gp  Method
 +1 -0.672856 0.04702022 -2.406425 10  1 pearson
 +>
 +> spcor.test(datavar$bankaccount, datavar$income, datavar$famnum)
 +   estimate  p.value statistic  n gp  Method
 +1 0.5646726 0.113182  1.810198 10  1 pearson
 +> spcor.test(datavar$bankaccount, datavar$famnum, datavar$income)
 +    estimate   p.value statistic  n gp  Method
 +1 -0.4086619 0.2748117 -1.184655 10  1 pearson
 +
 +
 + 
 +</code>
sequential_regression.txt · Last modified: 2022/05/22 21:50 by hkimscil

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