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normal_distribution [2017/03/24 08:39] hkimscilnormal_distribution [2017/03/24 08:42] hkimscil
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 \displaystyle P(x) = \frac{1}{\sqrt{2 \pi \sigma^2}} * e^{\frac{-(x - \mu)^2}{2 \sigma^2}}  \displaystyle P(x) = \frac{1}{\sqrt{2 \pi \sigma^2}} * e^{\frac{-(x - \mu)^2}{2 \sigma^2}} 
 \end{equation}   \end{equation}  
- 
 위에서 $\pi$와  $e$ 는 각각 $\pi = 3.1416, e=2.7183 $으로 상수 위에서 $\pi$와  $e$ 는 각각 $\pi = 3.1416, e=2.7183 $으로 상수
  
 +특히 평균이 0 이고 그 표준편차가 1인 정상분포를 표준정상분포라고 한다. 
  
 +{{http://math.arizona.edu/~rsims/ma464/standardnormaltable.pdf|표준정규분포 table]]
  
normal_distribution.txt · Last modified: 2024/03/13 08:28 by hkimscil

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