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b:head_first_statistics:geometric_binomial_and_poisson_distributions

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b:head_first_statistics:geometric_binomial_and_poisson_distributions [2024/10/28 08:26] – [Broken Cookies case] hkimscilb:head_first_statistics:geometric_binomial_and_poisson_distributions [2024/10/28 08:37] (current) – [Broken Cookies case] hkimscil
Line 1232: Line 1232:
 b(100, 0.1)이므로  b(100, 0.1)이므로 
 n*p = 10 = lambda  n*p = 10 = lambda 
-따라서+따라서 Pois 분포로 보는 답은  
 +lambda = 10 일때 P(r=15)값을 구하는 문제로  
 + 
 +\begin{eqnarray*} 
 +P(r = 15) & = & e^{-10} * \frac {10^{15}}{15!} \\ 
 +& = & 0.0347180 
 +\end{eqnarray*}
 <code> <code>
 > dpois(x=15, lambda=10) > dpois(x=15, lambda=10)
b/head_first_statistics/geometric_binomial_and_poisson_distributions.1730071592.txt.gz · Last modified: 2024/10/28 08:26 by hkimscil

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